1. For example, we have y = x2 + 4x + 4
2. Remember the basic form for quadratic function is ax2 + bx + c then, we can remember if the value of a positive then it has right side up so it has minimum point if the value of a is negative then it has upside down so it has maximum point
3. In this case we have minimum point (vertex)
. 4. First, find the vertex of function above, by using -b / 2a to find point x in vertex.
5. Then, to find the value of y in vertex we can substitute the value of x, for example :
x = -b / 2a = -4 / 2(1) = -2
then, y = x2 + 4x + 4
y = (-2)2 + 4(-2) +4
y = 4 – 8 + 4
y = 0
so, the vertex is (-2,0)
6. Then, we can find the additional point to make us easier to sketch the graph
For this case,
Point substitute | (-2)2 + 4(-2) +4 | Result |
-7 | (-7)2 + 4(-7) +4 | 25 |
-6 | (-6)2 + 4(-6) +4 | 16 |
-5 | (-5)2 + 4(-5) +4 | 9 |
-4 | (-4)2 + 4(-4) +4 | 4 |
-3 | (-3)2 + 4(-3) +4 | 1 |
-2 | (-2)2 + 4(-2) +4 | 0 |
-1 | (-1)2 + 4(-1) +4 | 1 |
0 | (0)2 + 4(0) +4 | 4 |
1 | (1)2 + 4(1) +4 | 9 |
2 | (2)2 + 4(2) +4 | 16 |
3 | (3)2 + 4(3) +4 | 25 |
Tidak ada komentar:
Posting Komentar